如何从列表中的列表中删除某些整数？

Question

I'm trying to make a blackjack game as a beginners project. When I try to remove the card that's being dealt from the deck I get this: ValueError: list.remove(x): x not in the list. How can I fix this?

This is my code:

import random

deck = [[2, 2, 2, 2],
        [3, 3, 3, 3],
        [4, 4, 4, 4],
        [5, 5, 5, 5],
        [6, 6, 6, 6],
        [7, 7, 7, 7],
        [8, 8, 8, 8],
        [9, 9, 9, 9],
        [10, 10, 10, 10],
        [10, 10, 10, 10],
        [10, 10, 10, 10],
        [10, 10, 10, 10],
        [11, 11, 11, 11]
        ]

def deal_cards():
    number = random.choice(deck[0:][0:]) # selecting the number of the card
    card = random.choice(number) # selecting which suit from the number should be the card
    new_deck = deck.remove(card) # Here is the problem
    print(new_deck)
    print(card)

deal_cards()

Answer 1

nested lists behave as lists of lists. That meaning you would have to specify an index of the first list to get access to the items in the nested list.

 new_deck = deck[foo].remove(card)

this goes into list[foo], for example let foo = 1. The list would be [3,3,3,3].

Answer 2

card is an int not list.That's why you are getting this error. Your deck contains list of lists. If you want to remove a single int then you should specify which list it should be removed. You should change your code as following:

 def deal_cards(): number = random.choice(deck[0:][0:])# selecting the number of the card card = random.choice(number)# selecting wich suit from the number deck[deck.index(number)].remove(card) # problem fixed print(deck) # remove returns nothing print(card)