整数的科学记数法

Question

I have a file in which values are in scientific notation 3.198304894802781462e+00 . I want to convert these in integers. I have tried this:

data = [int(float(number))
            for line in open('data.txt', 'r')
                for number in line.split()]

Error:

could not convert string to int: '1.874475383557408747e+01,3.627623082212955374e+00,9.037237691778705084

Answer 1

you can use the context manager to read from your file:

data = []
with open('data.txt', 'r') as fp:
    for line in fp.readlines():
        for number in line.split(','):
            data.append(int(float(number.strip())))

if you want to append the data list to your file:

with open('data.txt', 'a') as fp:
    fp.write(",".join(str(e) for e in data))

Answer 2

Judging by your error message, your numbers are delimited by , , not whitespace. You must therefore use line.split(',') instead.

with open('data.txt', 'r') as in_stream:
    data = [
        int(float(number))
        for line in in_stream
        for number in line.split(',')
    ]

Answer 3

try something like this. you need to split the string and then apply the float function on every item:

a = '1.874475383557408747e+01,3.627623082212955374e+00,9.037237691778705084'
b = a.split(',')
print(b)

for n in b:
    print(float(n))

or simply:

res = [float(n) for n in a.split(',')]

I assumed that you have your data as string but from your example this should work:

data = [int(float(number))
            for line in open('data.txt', 'r')
                for number in line.split(',')]