正则表达式：在一些特殊字符后将非 ascii 字符大写

Question

I tried this code to capitalize each non-ascii character or simple letter in a string after a space or a special character like "-", but it doesn't work :

var re = /(\b[a-z](?!\s))/g;
var name = "jean-àris-sa ça";
name = name.replace(re, function(x){return x.toUpperCase();});
console.log(name) // Jean-àRis-Sa çà

Expected result would be "Jean-Àris-Sa Ça", how can I achieve that ?

Answer 1

You may use

 console.log( "jean-àris-sa ça".replace(/(-|\\s+|^)(.)/g, function(_,$1,$2) { return $1 + $2.toUpperCase(); } ) )

The (-|\\s+|^)(.) pattern captures - or 1+ whitespaces (or just start of string position, an empty string) into Group 1 and any next char into Group 2 and returns the same string with that char in Group 2 turned into upper case.

As you may need to upper the first letter while lowering the rest of the letters in the same word, you may need a regex to match all letters. XRegExp library can work for you in all browsers:

 var regex = XRegExp("(\\\\pL)(\\\\pL*)"); console.log( XRegExp.replace("jean-àRiS-sa çA", regex, function(_, $1, $2) { return $1.toUpperCase() + $2.toLowerCase(); }, "all") );

 <script src="https://cdnjs.cloudflare.com/ajax/libs/xregexp/3.2.0/xregexp-all.min.js"></script>

In the latest Chrome versions that support ECMAScript 2018 you may simply use

 console.log( "jean-àRiS-sa çA".replace(/(\\p{L})(\\p{L}+)/gu, (_, $1, $2) => $1.toUpperCase() + $2.toLowerCase()) );

The \\pL or \\p{L} Unicode category matches any letter.