[英]Pandas: search list of keywords in the text column and tag it
I have bag of words as elements in a list format. 我有一些单词作为列表格式的元素。 I am trying to search if each and every single of these words appear in the pandas data frame ONLY if it 'startswith' the element in the list.
我试图搜索这些单词中的每一个单词是否仅出现在pandas数据框中,如果它'以“列表中的元素开头”。 I have tried 'startswith' and 'contains' to compare.
我试过'startswith'和'contains'进行比较。
Code: 码:
import pandas as pd
# list of words to search for
searchwords = ['harry','harry potter','secret garden']
# Data
l1 = [1, 2, 3,4,5]
l2 = ['Harry Potter is a great book',
'Harry Potter is very famous',
'I enjoyed reading Harry Potter series',
'LOTR is also a great book along',
'Have you read Secret Garden as well?'
]
df = pd.DataFrame({'id':l1,'text':l2})
df['text'] = df['text'].str.lower()
# Preview df:
id text
0 1 harry potter is a great book
1 2 harry potter is very famous
2 3 i enjoyed reading harry potter series
3 4 lotr is also a great book along
4 5 have you read secret garden as well?
Try #1: 尝试#1:
When I run this command it picks it up and gives me the results through out the text column. Not what I am looking for. I just used to check if I am doing things right for an example reasons for my understanding.
df[df['text'].str.contains('|'.join(searchwords))]
Try #2: When I run this command it returns nothing. 尝试#2:当我运行此命令时,它什么都不返回。 Why is that?
这是为什么? I am doing something wrong?
我做错了什么? When I search 'harry' as single it works, but not when I pass in the list of elements.
当我将'harry'作为单一搜索时,它可以正常工作,但是当我传入元素列表时却不行。
df[df['text'].str.startswith('harry')] # works with single string.
df[df['text'].str.startswith('|'.join(searchwords))] # returns nothing!
Use startswith
with a tuple
使用带有
tuple
startswith
Ex: 例如:
searchwords = ['harry','harry potter','secret garden']
# Data
l1 = [1, 2, 3,4,5]
l2 = ['Harry Potter is a great book',
'Harry Potter is very famous',
'I enjoyed reading Harry Potter series',
'LOTR is also a great book along',
'Have you read Secret Garden as well?'
]
df = pd.DataFrame({'id':l1,'text':l2})
df['text'] = df['text'].str.lower()
print(df[df['text'].str.startswith(tuple(searchwords))] )
Output: 输出:
id text
0 1 harry potter is a great book
1 2 harry potter is very famous
since startswith
accepts str and no regex, use str.findall
因为
startswith
接受str而没有正则表达式,所以使用str.findall
df[df['text'].str.findall('^(?:'+'|'.join(searchwords) + ')').apply(len) > 0]
Output 产量
id text
0 1 harry potter is a great book
1 2 harry potter is very famous
You could pass a tuple in startswith
function to check for multiple words See this str.startswith with a list of strings to test for 您可以在
startswith
函数中传递一个元组以检查多个单词请参阅此str.startswith以及要测试的字符串列表
In your case, you can do 在你的情况下,你可以做到
df['text'].str.startswith(tuple(searchwords))
Out:
0 True
1 True
2 False
3 False
4 False
Name: text, dtype: bool
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