在文件中查找多行文本

Question

I need to extract the fields name between opening and closing round brackets of the unique index and this can span in 2 or 3 or multiple lines

Here is the content of the file:

create index "informix".be_ach_detail_1_ix1 on "informix".be_ach_detail_1 (association,bank_number,batch_date) using btree ; 
create unique index "informix".bank_info_pk on "informix" .bank_info 
(merchant,bank_number,batch_date,sequence_number, association,transaction_code,ach_table) using btree ;  

Expected output:

(merchant,bank_number,batch_date,sequence_number, association,transaction_code,ach_table)

I have tried multiple findall options but it's not working:

myfile=re.findall(r'unique index\s.*\S*\)',myfile)[0]
myfile=re.findall(r'unique index\s.*\S*\)',myfile)[0]

Answer 1

You can use pattern = r"unique index[^(]*\\(([^)]*)\\)" which means:

• unique index search for exactly this substring in the text
• [^(]* match all characters except ( which will be the text until the bracket opens with (
• \\( the opening bracket (we have to escape the character with a backslash)
• ([^)]*) the group which matches all characters except ) which will be the text until the bracket closes with )
• \\) the closing bracket (we have to escape the character with a backslash)

import re

text = """create index "informix".be_ach_detail_1_ix1 on "informix".be_ach_detail_1 (association,bank_number,batch_date) using btree ; create unique index "informix".bank_info_pk on "informix" .bank_info (merchant,bank_number,batch_date,sequence_number, association,transaction_code,ach_table) using btree ;"""

pattern = r"unique index[^(]*\(([^)]*)\)"
print(re.findall(pattern, text))

Which prints:

['merchant,bank_number,batch_date,sequence_number, association,transaction_code,ach_table']