有没有解决方案可以比较SQL全文搜索中的特定字段？

Question

This is my regular code and it works fine:

$sql = 'SELECT '
    . '* '
  . 'FROM '
    . 'item '
  . 'WHERE MATCH '
    . '(title) '
  . 'AGAINST '
    . '(:search IN NATURAL LANGUAGE MODE) '
  . 'OR MATCH '
    . '(description) '
  . 'AGAINST '
    . '(:search IN NATURAL LANGUAGE MODE) '
  . 'ORDER BY '
    . 'id ASC';

I want to compare the field "status" to the string "public" because I need only the "public" entrys, I tried something like this:

$sql = 'SELECT '
    . '* '
  . 'FROM '
    . 'item '
  . 'WHERE MATCH '
    . '(title) '
  . 'AGAINST '
    . '(:search IN NATURAL LANGUAGE MODE) '
  . 'OR MATCH '
    . '(description) '
  . 'AGAINST '
    . '(:search IN NATURAL LANGUAGE MODE) '
  . 'WHERE '
    . 'status = "public" '
  . 'ORDER BY '
    . 'id ASC';

But with the last "WHERE" the result is nothing I expected.

Is there any solution?

Answer 1

You have added 2 WHERE statements, thats not allowed and when you use OR it is best to place brackets round the OR condition to ensure the correct result

$sql = 'SELECT *
        FROM item 
        WHERE status = "public"
        AND (
                MATCH (title) AGAINST (:search IN NATURAL LANGUAGE MODE) 
             OR MATCH (description) AGAINST (:search IN NATURAL LANGUAGE MODE) 
            )
        ORDER BY id ASC';

Answer 2

There are couple of errors in your query,

1. WHERE clause is added twice

2. Conditions in OR should be enclosed in round brackets '()'

    SELECT * FROM item WHERE ( MATCH (title) AGAINST (:search IN NATURAL LANGUAGE MODE) OR MATCH (description) AGAINST (:search IN NATURAL LANGUAGE MODE) ) AND status = "public" ORDER BY id ASC 

Also, using SELECT * is harmful. You can read the details about it here