[英]Function doesn't return correct value using pointers in C
This is a program to calculate the prize for all friends who contributed for a bet. 这是一个计算为所有下注的朋友计算奖金的程序。 The reward is based on how much each one contributed with money.
奖励基于每个人用钱捐款多少。 But the function i created is returning 0.0000 for all.
但是我创建的函数将全部返回0.0000。
a little dictionary: 一些字典:
int main(){
int exerc;
printf("Digite o numero do exercicio desejado: ");
printf("\n");
scanf("%d", &exerc);
switch (exerc){
case 2:{
float aposta1, aposta2, aposta3, premio;
printf("Digite respectivamente o valor que cada um apostou: ");
scanf("%d %d %d", &aposta1, &aposta2, &aposta3);
printf("Digite o valor do premio: ");
scanf("%d", &premio);
void exercicio2(float *, float*, float*, const float*);
exercicio2(&aposta1, &aposta2, &aposta3, &premio);
printf("O valor que o primeiro apostante recebera e de: %f", aposta1);
printf("\nO valor que o segundo apostante recebera e de: %f", aposta2);
printf("\nO valor que o terceiro apostante recebera e de: %f", aposta3);
}
}
return 0;
}
void exercicio2(float *ap1, float *ap2, float *ap3, const float *premio){
float total;
total = *ap1 + *ap2 + *ap3;
*ap1 = (*ap1/total) * (*premio);
*ap2 = (*ap2/total) * (*premio);
*ap3 = (*ap3/total) * (*premio);
}
An expected value for input (bets) aposta1 = 50, aposta2 = 25, aposta3 = 25 and premio(prize) = 1000, would be: ap1 = 500, ap2 = 250, ap3 = 250. 输入(下注)aposta1 = 50,aposta2 = 25,aposta3 = 25和premio(prize)= 1000的期望值将是:ap1 = 500,ap2 = 250,ap3 = 250。
but it's occurring: 但它正在发生:
"C:\Users\Marco Antonio\CLionProjects\untitled\cmake-build-debug\untitled.exe"
Digite o numero do exercicio desejado: 2
Digite respectivamente o valor que cada um apostou:50 25 25
Digite o valor do premio:1000
O valor que o primeiro apostante recebera e de: 0.000000
O valor que o segundo apostante recebera e de: 0.000000
O valor que o terceiro apostante recebera e de: 0.000000
Changing the format specifier ( %d
to %f
) will solve the issue: 更改格式说明符(
%d
到%f
)将解决此问题:
scanf("%d %d %d", &aposta1, &aposta2, &aposta3);
scanf("%d", &premio);
to 至
scanf("%f %f %f", &aposta1, &aposta2, &aposta3);
scanf("%f", &premio);
The issue was you are entering a floating point number and your program is reading the integer. 问题是您输入的是浮点数,而程序正在读取整数。 In such case, the behaviour is undefined.
在这种情况下,行为是不确定的。 Please take a look at a SO question and it's answer about format specifier and undefined behaviour.
请看一个SO问题,它是有关格式说明符和未定义行为的答案 。
Standard specifies: 标准规定:
If any argument is not the correct type for the corresponding conversion specification, the behavior is undefined.
如果任何参数都不是相应转换规范的正确类型,则行为未定义。
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