使用stdin读取文本文件，然后遍历多个数组

Question

I got a text file that is a single line of a string. For example:

I'm John

I need to read the file using stdin then traverse each characters into multiple arrays where each row shifts to the left by one character:

row1 = [I, ' , m , , J , o , h , n]

row2 = [' , m , , J, o , h, n , I ]

row3 = [m , , J , o , h, n, I , ' ]

row4 = [, , J , o , h , n , I , ' , m]

...

rown = [n , I , ' , m , , J , o , h ]

It is important to note the length of the arrays and number of arrays I create are variable that are dependent on the length of the string from the text file (n*n). In this case it would be 8*8 characters, so I need to create 8 arrays with 8 length each. Any help please?

Answer 1

I would read the data into an std::string .

I'd create an std::vector<std::string> to hold all the results.

I'd use the vector's push_back member to append a string to the vector.

Then I'd use std::rotate to rotate the string by one character.

I'd repeat appending and rotating for as many characters as the string contains.

Answer 2

Jerry is correct and gives a crisp solution to your problem. You can perhaps have it better using std::vector<std::vector<char> > to hold the data and doing something like:

int i = 0;
do
{
    for (int j = 0; j < len; j++)
    {
        data[i][j] = input[(i+j)/len];
    }
} while (i++ < len) // len is 8 in your case