当一个函数有多个参数时设置去抖动lodash

Question

When I don't have parameters in function I set debounce in this way: search = debounce ((query) => this.getTask(query), 1000); . And how to set debounce when I have several parameters?

  search = debounce ((query) => {
     this.setState ({
       query
     }, () => this.getTask(userId, query, status)
})

Answer 1

The number of parameters doesn't make a difference to debounce , it will pass everything to your function.

 const search = _.debounce((param1, param2) => { console.log(param1); console.log(param2); }, 1000); search('hi', 'hello'); 

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