[英]Removing phrases with custom stop words from a list
I have two lists 我有两个清单
listA = ['New Delhi', 'Moscow', 'Berlin', 'France', 'To Washington']
stopwordlist = ['new', 'To']
I am trying to get something like this 我正在尝试得到这样的东西
finalList = ['Moscow', 'Berlin', 'France']
What I have tried until now works if I am looking for whole words: 如果我一直在寻找完整的单词,那么直到现在我尝试过的东西仍然有效:
listB = []
for item in listA:
if item not in stopwordlist:
listB.append(item)
else:
continue
....
....
return listB
We may split the item
then check those in the stopwordlist. 我们可以拆分item
然后检查停用词列表中的项目。 But this seems like to many workarounds. 但这似乎是许多解决方法。 Or I could use a regex re.match
. 或者我可以使用正则表达式re.match
。
Here is one way to do this, 这是一种方法,
>>> listA = ['New Delhi', 'Moscow', 'Berlin', 'France', 'To Washington']
>>> stopwordlist = ['new', 'To']
>>> finalList = [i for i in listA if not any(j.lower() in i.lower() for j in stopwordlist)]
>>> finalList
['Moscow', 'Berlin', 'France']
or You could use the builtin filter
function. 或者您可以使用内置的filter
功能。
>>> listA = ['New Delhi', 'Moscow', 'Berlin', 'France', 'To Washington']
>>> stopwordlist = ['new', 'To']
>>> list(filter(lambda x: not any(j.lower() in x.lower() for j in stopwordlist), listA))
['Moscow', 'Berlin', 'France']
sl = tuple(i.lower() for i in stopwordlist)
[i for i in listA if not i.lower().startswith(sl)]
Output 产量
['Moscow', 'Berlin', 'France']
listA =['New Delhi','Moscow', 'Berlin','France', 'To Washington']
stopwordlist = ['new','To']
listA = [i.lower() for i in listA]
stopwordlist = [i.lower() for i in stopwordlist]
listB =[]
for item in listA:
flag = True
for i in item.split(' '):
if i in stopwordlist:
flag =False
if flag:
listB.append(item)
print(listB)
you have to lower your stop words also the words against you run you stopwords: 您必须降低停用词,也要降低针对您的词使您停用词:
listA = ['New Delhi', 'Moscow', 'Berlin', 'France', 'To Washington']
stopwordlist = ['new', 'To']
stop_words = {e.lower() for e in stopwordlist}
finalList = [e for e in listA if not stop_words.intersection(e.lower().split())]
or you can use regex: 或者您可以使用正则表达式:
import regex as re
stop_words_regex = re.compile(r"\L<words>", words=stop_words)
finalList = [e for e in listA if not stop_words_regex.findall(e.lower())]
Output: 输出:
['Moscow', 'Berlin', 'France']
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