在Javascript中获取两个字符串之间的字符串

Question

I have the below string that I need help pulling an ID from in Presto. Presto uses the javascript regex. I've searched multiple options including:

JavaScript text between double quotes

Javascript regex to extract all characters between quotation marks following a specific word

I need to pull the GA Client ID which looks like this: 75714ae471df63202106404675dasd800097erer1849995367

Below is a snipped where it sits in the string.

The struggle is that the "s:38:" is not constant. The number can be anything. For example, it could be s:40: or s:1000: etc. I need it to return just the alphanumeric id.

String Snippet

"GA_ClientID__c";s:38:"75714ae471df63202106404675dasd800097erer1849995367";

Full string listed below

99524";s:9:"FirstName";s:2:"John";s:8:"LastName";s:8:"Doe";s:7:"Company";s:10:"Sample";s:5:"Email";s:20:"xxxxx@gmail.com";s:5:"Phone";s:10:"8888888888";s:7:"Country";s:13:"United States";s:5:"Title";s:8:"Creative";s:5:"State";s:2:"NC";s:13:"Last_Asset__c";s:40:"White Paper: Be a More Strategic Partner";s:16:"Last_Campaign__c";s:18:"70160000000q6TgAAI";s:16:"Referring_URL__c";s:8:"[direct]";s:19:"leadPriorityMarketo";s:2:"P2";s:18:"ProductInterest__c";s:9:"sample";s:14:"landingpageurl";s:359:"https://www.sample.com;mkt_tok=samplesamplesamplesample";s:14:"GA_ClientID__c";s:38:"75714ae471df63202106404675dasd800097erer1849995367";s:13:"Drupal_SID__c";s:36:"e1380c07-0258-47de-aaf8-82d4d8061e1a";s:4:"form";s:4:"1046";} ```

Answer 1

This works for your sample

"GA_ClientID__c";[^"]*"([^"]*)"

https://regex101.com/r/Q4Orj6/1