Python timeit模块导致无限循环

Question

Consider this Python3 code:

def classic_fibonacci(limit: int) -> List[int]:
    nums = []
    curr, nxt = 0, 1

    while curr < limit:
        curr, nxt = nxt, nxt + curr
        nums.append(curr)

    return nums

def classic_fib_profiling():
    for n in classic_fibonacci(limit=1000):
        print(n, end=', ')

if __name__ == '__main__':
    import timeit
    timeit.timeit("classic_fib_profiling()", setup="from __main__ import classic_fib_profiling")

Calling classic_fib_profiling() returns, as expected, a single list of Fibonacci numbers, limited to limit parameter.

Calling it using timeit.timeit , on the other hand, causes the interpreter to go into an infinite loop, never stopping. I wasn't able to find a solution by debugging or searching docs (and SO). Any help would be appreciated.

Answer 1

It is not going in an infinite loop. It will run the same function number times (default: number=1000000 ). Just wait for it finish, or provide the number of times the loop should run. Check the arguments for the timeit.timeit function.

Help on function timeit in module timeit:

timeit(stmt='pass', setup='pass', timer=, number=1000000, globals=None) Convenience function to create Timer object and call timeit method.

Change the line from,

>>> timeit.timeit("classic_fib_profiling()", setup="from __main__ import classic_fib_profiling")

to

>>> timeit.timeit("classic_fib_profiling()", setup="from __main__ import classic_fib_profiling", number=1)

and observe :)