如何仅打印出真实的对象值？

Question

I am learning Javascript, and am making a simple user verification object. I need a function that will console.log only users who have "isVerified" set to true.

I have tried numerous ways including loops and if statements. The function name is "showVerified" below.

var person = {
    info: [],
    displayPerson: function() {
        console.log('People', this.info);
    },
    addPerson: function(age, firstName, lastName) {
        this.info.push({
            age: age,
            firstName: firstName,
            lastName: lastName,
            isVerified: false
        });
        this.displayPerson();
    },
    deletePerson: function(position) {
        this.info.splice(position, 1);
        this.displayPerson();
    },
    verifyPerson: function(position) {
        this.info[position].isVerified = true;
        this.info[position].firstName = this.info[position].firstName.toUpperCase();
        this.displayPerson();
    },
    showVerified: function() {
        for (var key in this.info) {
            if (this.info.isVerified = true) {
                console.log(this.info.isVerified[key]);
            }
        }
    }
}

What I want to happen when running showVerified on my person object, is for it to print out ONLY the age, first name, and last name of any person who is verified.

Answer 1

I suggest trying to change the way you're naming your properties, so the code is a bit clearer. Try

showVerified: function() {
        this.info.filter(x => x.isVerified).forEach(v => console.log(v))
    }

Answer 2

if you don't want to use filter, you can try this as well

this.info.forEach(person => {
   if(person.isVerified){
   console.log(person);
   }
});