如何计算所有行2列中的不同值

Question

I have 2 columns,and I am looking for a count of all distinct values in BOTH columns overall, not just the same row in both columns. IE here the count of distinct values is 9 because 1000, 5000, 7000 and 8000 will only be included once.

 x          y
 1000    NULL
 2000    1000
 3000    1000
 4000    1000
 5000    1000
 6000    5000
 7000    5000
 8000    7000
 9000    8000

Answer 1

You can unpivot the data and count:

select count(distinct x)
from ((select x from t) union all
      (select y from t)
     ) t;

That said, it looks like the first column is unique and has the information you want, so perhaps you simply want:

select count(*)
from t;

Or:

select count(distinct x)
from t;

Answer 2

Union is the way to go

    Select count(*) from(Select x from 
    table tx 
   union
   Select y from table ty) ;