Selenium find_element_by_link_text无法用于完整网址

Question

I'm working on a Python/Selenium program that makes a file of urls I've visited, then highlights them in the browser when I do a Google Search so I don't waste time visiting these sites again.

#searched Google for: "county fair" site:etypeservices.com
element = driver.find_element_by_partial_link_text("etypeservices.com")
driver.execute_script("arguments[0].style.backgroundColor = 'yellow'", element)

So far, so good. But if I try to select the full webpage using the same method...

element = driver.find_element_by_link_text("http://archives.etypeservices.com/Wauneta1/Magazine132532/Publication/Magazine132532.pdf")

I get the following error:

selenium.common.exceptions.NoSuchElementException: Message: Unable to locate element

Any ideas why this is happening?

Answer 1

As per find_element_by_partial_link_text function documentation:

Finds an element by a partial match of its link text.

Args :

link_text: The text of the element to partially match on.

Given you have the following link definition:

<a href="http://example.com">Example Domain</a>

You can match it like:

driver.find_element_by_partial_link_text("Example")

or

driver.find_element_by_partial_link_text("Domain")

If you want to locate the element by its partial URL you need to use href attribute , it can be done using XPath Selector and XPath contains() function like:

driver.find_element_by_xpath("//a[contains(@href,'http://example.com')]")