REGEX从图像文件名获取元素

Question

I need to parse a set of filenames with the next pattern:

A0001L+23.20K+01-Red.JPG

Into the followed elements:

• Get the first Number -> 0001
• Get the L value -> 23.20 (Could be positive or negative number)
• Get the K value -> 01 (Could be positive or negative number)
• Get the color -> Red

I'm using the the approach of REGEX groups using the next pattern:

IMAGE_PATTERN = "[A-Z](\\d\\d\\d\\d)[A-Z][-|\\+](\\d\\d\\.\\d\\d)[A-Z][-|\\+](\\d\\d)-([A-Za-z]+)(\\.[A-Za-z]+)";

But is not working correctly, is the IMAGE_PATTERN, set it right?

Answer 1

I have tested below pattern and it works:

[a-zA-Z]([0-9]{4})L\+([0-9\.]+)K([+\-][0-9]+)\-([a-zA-Z]+)

You can modify it to suit your needs.

You may check out the below link

Regex101Link

Answer 2

I think you are after this, includes fetching +/- as well

[a-zA-Z](\d{4})[A-Z]([+\-]\d{2}\.\d{2})K([+\-][0-9]+)\-([a-zA-Z]+)

Regex Test Link