尝试通过使用另一个表中的id值将两个表连接在一起

Question

So i'm pretty new to sql and i'm trying to figure out how to connect two tables together.

I have a table named customers and a table named pets and i want to assign the pets to specific customers. I am able to assign them a customer value but only as the id, i can't figure out how to take that id and change it to say, a customer name when i reference it back in a table that displays my data.

so for example in my customer table the customer id = 10; customerName = "John Smith"; customer id = 10; customerName = "John Smith";

then i have the pets table petId = 16; petName = Alfredo; customerId = 10; petId = 16; petName = Alfredo; customerId = 10;

Is there a way to reference that customerID = 10 back to the customer table from the pets table so I can pull the name of the customer instead of the id?

this is my code to display the table that list the pets query, where $row['customer'] I want to show the customer name, not the id.

Thanks

        <?php 
      $sql = "SELECT * from pets ORDER BY petName ASC";

      echo "<table class='tableInfo' cellpadding='8'>";
      echo "<tr><th>Pet Name</th><th>Owner</th><th colspan='2'>Action</th></tr>";
      $result = mysqli_query($con, $sql);

      while($row = mysqli_fetch_array($result)){    
          echo "<tr>";    
          echo '<td>' . $row['petName'] .'</td>';    
          echo '<td>' . $row['customerId'] .'</td>'; 
          echo '<td><a href="editPets.php?id=' . $row['id'] . '">Edit</a></td>';    
          echo '<td><a href="deletePets.php?id=' . $row['id'] . '">Delete</a></td>';    
          echo "</tr>";    
    }
        echo "</table>";     
    ?>

Answer 1

Yes hi there, you can definitely do that with an inner join:

select * from pets
join customers on pets.customerId = customers.customerId
order by petName

It sounds the query may be returning an error. Perhaps print the error with:

$res = mysqli_query($con, $sql) or die ('Query failed: ' . mysqli_error($con));

while ($row = mysqli_fetch_assoc($res)) {
    // Do something with row
}