新编码器：TypeError：列表索引必须是整数或切片，而不是元组

Question

I am writing some code to print high scores from a file. I am new to python and therefore don't have much experience. It'd be great to be told where I am going wrong and how to fix it:)

Please note the code may not be efficient!!!

Searching up the problem and looking to friends for advice, coming from a background with no prior coding knowledge, no one around me knows how to help!

file = open("scores.txt", "r")
for line in file:
    filecont = line.split(",")
listOfInt = filecont[::2]
listOfStr = filecont[1::2]
intoDict = zip(listOfStr, listOfInt)
dictOfWords = dict(intoDict)
sortedbyValueDict = sorted(dictOfWords.items(), key = lambda t:t[1]) 
print("\n<<< HIGH SCORES >>>\n")
counter = 0
for i in sortedbyValueDict:
    print(i, ':', sortedbyValueDict[i])
    counter = counter + 1
    if counter == 5:
        break

Scores.txt is as follows:

7,jacob,5,rishikesh,3,alex,2,oliver,9,piers

I expect the output to be a sorted print of the top 5 high scores in order, however I am getting the error message:

TypeError: list indices must be integers or slices, not tuple

Thank you anyone who helps!

Answer 1

Try this

import sys

file = open("input.txt", "r")

for line in file:
    filecont = line.split(",")
listOfInt = filecont[::2]
listOfStr = filecont[1::2]
intoDict = zip(listOfStr, listOfInt)
dictOfWords = dict(intoDict)

print(dictOfWords)

sortedbyValueDict = sorted(dictOfWords.items(), key = lambda t:t[1], reverse=True)
print("\n<<< HIGH SCORES >>>\n")
counter = 0
for i in sortedbyValueDict:
    print(counter, ':', i)
    counter = counter + 1
    if counter == 5:
        break

This will give you the result:

<<< HIGH SCORES >>>

0 : ('piers', '9')
1 : ('jacob', '7')
2 : ('rishikesh', '5')
3 : ('alex', '3')
4 : ('oliver', '2')

You can remove reverse=True if you want it in ascending order.

Answer 2

You are confusing two different types of iterations.

When you run the following:

l = ['A', 'B', 'C']
for i in l:
    print(i)

The output will be:

A
B
C

If you want to treat i as an integer like in most other languages, you need to use the range function:

for i in range(3):
    print(i)

output:

0
1
2

if you want to iterate over a list in this manner, you need to combine range with the len function, which returns the length of a list:

for i in range(len(l)):
    print(l[i])

output:

A
B
C

In your case, the following will fix your error:

for i in sortedbyValueDict:
    print(i)
    counter = counter + 1
    if counter == 5:
        break

or:

for i in range(len(sortedbyValueDict)):
    print(i, ':', sortedbyValueDict[i])
    counter = counter + 1
    if counter == 5:
        break