如何通过比较同一数组的任何一个或两个值来合并和求和值
[英]How merge and sum values by comparing any one or two values of the same array
问题描述
Below is the array in php and I need function to solve n numbers of array as displayed in Expected result by summing the (2) and (3) values if (0) and (1) are matching:
下面是 php 中的数组，如果 (0) 和 (1) 匹配，我需要 function 通过对 (2) 和 (3) 值求和来解决预期结果中显示的 n 个数组：
Array
(
[0] => Array
(
[0] => Array
(
[0] => Week - 1
[1] => 2019-08-05
[2] => 1
[3] => 2
)
[1] => Array
(
[0] => Week - 2
[1] => 2019-08-12
[2] => 3
[3] => 4
)
[2] => Array
(
[0] => Week - 3
[1] => 2019-08-19
[2] => 5
[3] => 6
)
)
[1] => Array
(
[0] => Array
(
[0] => Week - 1
[1] => 2019-08-05
[2] => 7
[3] => 8
)
[1] => Array
(
[0] => Week - 2
[1] => 2019-08-12
[2] => 9
[3] => 10
)
[2] => Array
(
[0] => Week - 3
[1] => 2019-08-19
[2] => 11
[3] => 12
)
[3] => Array
(
[0] => Week - 4
[1] => 2019-08-26
[2] => 13
[3] => 14
)
)
)
Expected Result:预期结果：
[0] => Array
(
[0] => Week - 1
[1] => 2019-08-05
[2] => 8
[3] => 10
)
[1] => Array
(
[0] => Week - 2
[1] => 2019-08-12
[2] => 12
[3] => 14
)
[2] => Array
(
[0] => Week - 3
[1] => 2019-08-19
[2] => 16
[3] => 18
)
[3] => Array
(
[0] => Week - 4
[1] => 2019-08-26
[2] => 13
[3] => 14
)
Need help to get the above expected result for the raised query.需要帮助才能获得上述查询的预期结果。 I tried below code:我尝试了以下代码：
<?php
$sum = [];
foreach($weekly as $aSet) {
foreach($aSet as $k => $kv) {
$i = 0;
foreach($kv as $v) {
$sum[$k][$i] += $v;
$i++;
}
}
}
?>
But it will add all types:但它会添加所有类型：
[0] => Array
(
[0] => 0
[1] => 4038
[2] => 8
[3] => 10
)
[1] => Array
(
[0] => 0
[1] => 4038
[2] => 12
[3] => 14
)
[2] => Array
(
[0] => 0
[1] => 4038
[2] => 16
[3] => 18
)
[3] => Array
(
[0] => 0
[1] => 4038
[2] => 13
[3] => 14
)
I want get sum only for 2 and 3rd value and need to keep constant for 0 and 1st value for exact match我只想获得第 2 和第 3 值的总和，并且需要保持第 0 和第 1 值的精确匹配
1 个解决方案
解决方案1
0 已采纳 2019-09-20 10:16:09
Because all your nested arrays are with predefined amount of elements, all of those with the same indexes, you can use a for loop instead of the third foreach :因为所有嵌套的 arrays 都具有预定义数量的元素，所有具有相同索引的元素，您可以使用for循环而不是第三个foreach ：
$sum = [];
foreach($weekly as $aSet)
{
foreach($aSet as $k => $kv)
{
$sum[$kv[0]][0] = $kv[0];
$sum[$kv[0]][1] = $kv[1];
for($i = 2; $i <= 3; $i++)
{
$sum[$kv[0]][$i] += $kv[$i];
}
}
}
echo "<pre>";
print_r($sum);
echo "</pre>";
With a for loop you can cycle inside the array considering only the needed elements of that array (in your case the indexes 0 and 1 aren't useful in this loop).使用for循环，您可以在数组内部循环，仅考虑该数组所需的元素（在您的情况下，索引0和1在此循环中没有用）。
Output: Output：
Array
(
[Week - 1] => Array
(
[0] => Week - 1
[1] => 2019-08-05
[2] => 8
[3] => 10
)
[Week - 2] => Array
(
[0] => Week - 2
[1] => 2019-08-12
[2] => 12
[3] => 14
)
[Week - 3] => Array
(
[0] => Week - 3
[1] => 2019-08-19
[2] => 16
[3] => 18
)
[Week - 4] => Array
(
[0] => Week - 4
[1] => 2019-08-26
[2] => 13
[3] => 14
)
)
If you prefer the array with numbered indexes do that:如果您更喜欢带有编号索引的数组，请执行以下操作：
echo "<pre>";
print_r(array_values($sum));
echo "</pre>";
Output: Output：
Array
(
[0] => Array
(
[0] => Week - 1
[1] => 2019-08-05
[2] => 8
[3] => 10
)
[1] => Array
(
[0] => Week - 2
[1] => 2019-08-12
[2] => 12
[3] => 14
)
[2] => Array
(
[0] => Week - 3
[1] => 2019-08-19
[2] => 16
[3] => 18
)
[3] => Array
(
[0] => Week - 4
[1] => 2019-08-26
[2] => 13
[3] => 14
)
)
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