[英]How to compare two rows with same column
I have data like below.我有如下数据。 I need to compare ATTRIBUTE1_TXT based on PART_KEY_ID.
我需要根据 PART_KEY_ID 比较 ATTRIBUTE1_TXT。 If both the date is same, i need that PART_KEY_ID.
如果两个日期相同,我需要那个 PART_KEY_ID。
PART_KEY_ID ATTRIBUTE1_TXT
504277 JUL 2019 (201)
504277 JUL 2019 (201)
5493605 JUL 2019 (201)
5493605 JUN 2018 (191)
4585233 JUL 2019 (201)
4585233 JUL 2019 (201)
6192893 JUL 2019 (201)
6192893 JUN 2018 (191)
so output should be.所以 output 应该是。
PART_KEY_ID
504277
4585233
select PART_KEY_ID
from your_table
group by PART_KEY_ID
having count(distinct ATTRIBUTE1_TXT) = 1
This should do what you want:这应该做你想要的:
select part_key_id
from t
group by part_key_id
having min(ATTRIBUTE1_TXT) = max(ATTRIBUTE1_TXT);
This should work这应该工作
select PART_KEY_ID from(select ATTRIBUTE1_TXT ,max(PART_KEY_ID),count(*) from table group by ATTRIBUTE1_TXT having count(*) >1)t;
--this will work
--if you got three similar ATTRIBUTE1_TXT for one PART_KEY_ID you can replace
----having count(*)=2 in cte to having count(*)=3
;with cte as (
select count(*) c,PART_KEY_ID,ATTRIBUTE1_TXT
from table
group by PART_KEY_ID,ATTRIBUTE1_TXT
having count(*)=2
)
select PART_KEY_ID
from cte
Try this query, I think it should satisfy your need.试试这个查询,我认为它应该满足你的需要。
SELECT PART_KEY_ID
FROM table_name
GROUP BY PART_KEY_ID, ATTRIBUTE1_TXT
HAVING COUNT(*) > 1
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