如何拆分正则表达式匹配

Question

I would like to match all given ( and ) in a string, but I'm having trouble because of my current solution matches () while my intention is got a split result like ['(',')']

My regex expression is: /[()]+/g , Regex101 playground .

How can I manage to get the desired behavior only with a regex expression?

 const matchType = str => str.match(/[()]+/g) console.log(matchType('{(})[]')); // ['(',')] // Expected ['(',')'] console.log(matchType('{[()]}')); // ['()']

Answer 1

Do not use quantifier + ,

when you use + quantifier + it means one or more time,

[()]+ this means match ( or ) one or more time, so when you have string like () it consider it as a single match

 const matchType = str => str.match(/[()]/g) console.log(matchType('{(})[]')); // ['(',')] // Expected ['(',')'] console.log(matchType('{[()]}'));

Answer 2

You just need to get rid of the + :

const matchType = str => str.match(/[()]/g)

The + means that you will match on one or more parens.