[英]Why “if” works but “switch” doesn't work?
// It is simple code
var num = prompt("put number");
// This way is not worked
switch (num) {
case num > 0:
console.log("num++");
break;
case num < 0:
console.log(num-2);
break;
}
// But this worked
if (num > 0){
console.log(num++);
} else if (num < 0){
console.log(num -2);
}
My first way by "switch" is not worked but "if" method worked.我的第一种“switch”方法不起作用,但“if”方法有效。
I tried all of thing for changing code or other ways but the same result.我尝试了所有更改代码或其他方式的方法,但结果相同。
Please guys help me.请大家帮帮我。
Because the statement num > 0
inside you case
will return true
or false
.因为
case
里面的语句num > 0
将返回true
或false
。 If you do this:如果你这样做:
switch (true) {
case num > 0:
console.log("num++");
break;
case num < 0:
console.log(num-2);
break;
}
It will work.它会起作用的。
Cases cannot be expressions, you must normalize your input first.
案例不能是表达式,您必须先规范化您的输入。
Although it is valid to place an expression in a case
, in this scenario a more tried-and-true way of dealing with this is to first normalize your input first.尽管在
case
中放置表达式是有效的,但在这种情况下,一种更可靠的处理方法是首先规范化您的输入。
You can determine direction for example:您可以确定方向,例如:
var num = parseInt(prompt("put number"), 10); var direction = num < 0? -1: 1; switch (direction) { case 1: console.log("num++"); break; case -1: console.log(num - 2); break; }
The switch acts as a case switcher, meaning you cannot make comparisons to create cases, just list cases by case, and perform some function from this case.该开关充当案例切换器,这意味着您无法进行比较来创建案例,只能逐个列出案例,并从该案例中执行一些 function。 The if / else structure is suitable for making comparisons, as the expected result in the if call is always a boolean.
if / else 结构适合进行比较,因为 if 调用中的预期结果始终是 boolean。
Example:例子:
const a = 1;
if (a === 1) {
console.log('hello');
} else {
console.log('sad');
switch (a) {
case 1 : console.log('hello'); break;
default: console.log('sad'); break;
In your case, I recommend using if/else if/else, as it is more recommended.在您的情况下,我建议使用 if/else if/else,因为更推荐使用它。
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