使用消息引发 ValueError，但不打印消息

Question

I have a FileNotFound error, which I would like to handle by raising a ValueError. The ValueError should come with a message, but this message shouldn't be displayed.

def check_file(file):
    try: 
        #open file here
    except FileNotFoundError: 
        raise ValueError("Caught a FileNotFoundError")
    except ValueError:
        print("This is the only thing I want shown) 

Current output:

FileNotFoundError: [Errno 2] No such file or directory: 'nonexistent_file.txt'

During handling of the above exception, another exception occurred:

ValueError: Caught a FileNotFoundError.

Desired output:

This is the only thing I want shown

Answer 1

You could wrap the call to the check_file function in try: ... except: as follows:

def check_file(file):
    try: 
        #open file here
    except FileNotFoundError: 
        raise ValueError("Caught a FileNotFoundError")

try:
    check_file("test")
except ValueError:
    print("This is the only thing I want shown")

Answer 2

I dont understand why you want to raise a ValueError. If you just want "This is the only thing I want shown" to show you can just do this

def check_file(file):
    try: 
        #open file here
    except FileNotFoundError:
        print("This is the only thing I want shown)

If you need to raise a ValueError please tell me why and ill try to figure it out but i dont believe its nessesary