将日期的月份和年份与日期行匹配

Question

I want to match a start date by month and year (regardless of the day) to a corresponding date that is a column header and return the column number of said date.

  Name    Start Date   1/7/2015   2/9/2016   4/25/2016  
 ------- ------------ ---------- ---------- ----------- 
  Steve   1/8/2015     100             350         700  
  Amy     2/2/2016     N/A             250         412  

The code I have tried is:

MATCH(1,(MONTH(B2)=MONTH($C$1:$E$1))*(YEAR(B2)=YEAR($C$1:$E$1)),0)

The response is "#Value" when it should return "1" for Steve and "2" for Amy.

Answer 1

As per my comment; this is an array formula. So either:

• Confirm the formula through holding Ctrl + Shift and only then press Enter

• Add in an additional INDEX , like so:

   =MATCH(1,INDEX((MONTH(B2)=MONTH($C$1:$E$1))*(YEAR(B2)=YEAR($C$1:$E$1)),),0)