找出前两位数字和后两位数字之和的平方等于数字本身的所有四位数字

Question

The program that I wrote it is not working and I really don't know why. I would really appreciate your help. Thank you

         for (int i = 1000; i <= 9999; i++){
             int n = i;
             int remandier1, remandier2,finalanswer;
             double result1=0;
             while(n != 0){
                 remandier1 = n % 100;
                 remandier2 = n /100;
                 finalanswer = remandier1 + remandier2;
                 result1 = Math.pow(finalanswer, 2);
             }
             if (result1 == n){
                 System.out.println(i);
             }
         }

So this program should execute all 4 digit numbers,the square of the sum of the first two digits and the last two digits should be equal to the number it self but mine it does nothing.

Answer 1

You are using a loop based on n being different from 0, but n is never modified during the loop. How would the loop could actually stop.. looping? May be I'm missing something, but as I see it, n will forever be equal to the set value of i .

while(n != 0)
{
    remandier1 = n % 100;
    remandier2 = n /100;
    finalanswer = remandier1 + remandier2;
    result1 = Math.pow(finalanswer, 2);
    // add something to stop the loop
    n = n - 1; // for example
}