[英]How to split string into list and trim in one line Java
Please look at my code请看我的代码
String Str = "E_1000, E_1005,E_1010 , E_1015,E_1020,E_1025";
List<String> splitStr = Arrays.asList(Str.split(","));
My list (splitStr) has strings with white spaces.我的列表(splitStr)有带空格的字符串。
Is there a way to split the string and trim all the elements in one line of code?有没有办法在一行代码中拆分字符串并修剪所有元素?
Yes, simply do:是的,只需执行以下操作:
String str = "E_1000, E_1005,E_1010 , E_1015,E_1020,E_1025";
List<String> splitStr = Arrays.stream(str.split(","))
.map(String::trim)
.collect(Collectors.toList());
Explanation:解释:
First, we split on ,
:首先,我们拆分
,
:
str.split(",")
Then, we turn it into a Stream of (untrimmed) Strings:然后,我们将其转换为(未修剪的)字符串的 Stream:
Arrays.stream(str.split(","))
Next, we trim all the Strings in the Stream:接下来,我们修剪 Stream 中的所有字符串:
Arrays.stream(str.split(","))
.map(String::trim)
Finally, we collect all the trimmed Strings into a List:最后,我们将所有修剪后的字符串收集到一个列表中:
Arrays.stream(str.split(","))
.map(String::trim)
.collect(Collectors.toList());
Just do a replacing of all whitespaces before doing iterations:只需在进行迭代之前替换所有空格:
String Str = "E_1000, E_1005,E_1010 , E_1015,E_1020,E_1025".replace(" ", "");
List<String> splitStr = Arrays.asList(Str.split(","));
Not sure whether single elements may contain spaces.不确定单个元素是否可能包含空格。 If not, simply remove all spaces:
如果没有,只需删除所有空格:
List<String> splitStr = Arrays.asList(Str.replace(" ", "").split(","));
MAYBE THIS WILL HELP YOU也许这会帮助你
ONE WAY:-单程:-
YOU CAN SAVE IT ON ANOTHER list splitStr2
您可以将其保存在另一个列表 splitStr2
List<String> ss = new ArrayList<String>();
for(String s:*splitStr*){ss.add(s.trim()); }
THIS ONE CHECK FOR NEW LIST ( WITHOUT_WHITESPACES )这个检查新列表( WITHOUT_WHITESPACES )
for(String temp:ss){System.out.println(temp);}
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