通过比较单词来比较字符串，只检查单词中相同数量的字母

Question

Given:

String s0 = "we wrocławiu"
String s1 = "w warszawie"

When:

Collator collator = Collator.getInstance(new Locale("pl", "PL"));
collator.setStrength(Collator.PRIMARY);
collator.setDecomposition(Collator.FULL_DECOMPOSITION);
int result = collator.compare(s0, s1);

Then:

assertTrue(result < 0);

But the result > 0.

How to compare strings to ignore the letter e ? So if it compares word with 3 letters to word with 5 letters it should only check 3 letters.

Answer 1

I would say:

Pseudo code:

// Find the length of the string which has the smallest length

// Truncate the other string so that they have both the same lengths

// Compare them