嵌入式形式 Symfony

Question

I have an user class that has a OneToOne relationship with Applicant and Company , I want to propose registering as one of both. In order to do that, I made 3 forms, an UserType (email) , an ApplicantType (firstName) and CompanyType (companyName) . According to url, I will either generate an ApplicantType or CompanyType to add to the UserType.

To pass the type I use

$form = $this->createForm(UserType::class, $user, ['data' => ['type' => $type]]);

so my UserType retrieves the type in $options and dynamically adds

->add('applicant', ApplicantType::class) or ->add('company',CompanyType::class)

I get an error which is

The form's view data is expected to be an instance of class App\Entity\User, but is a(n) array. You can avoid this error by setting the "data_class" option to null or by adding a view transformer that transforms a(n) array to an instance of App\Entity\User.

What I want to do in the end is, after submit, create and hydrate an Applicant/Company entity that I'll attach to a newly created User entity.

Answer 1

Two things solved it:

The data passed to the form should be

$form = $this->createForm(UserType::class, $user, ['typeOfUser' => $type]);

instead of

$form = $this->createForm(UserType::class, $user, ['data' => ['type' => $type]]);

Then in the formType add the default value for the key we use to pass the data

public function configureOptions(OptionsResolver $resolver)
{
    $resolver->setDefaults([ 
       'typeOfUser' => 'applicant'
    ]);
}