如何按配置文件 model (1:1) 中的字段对用户 model 进行排序？

Question

skill_note_reputation is a field in the Profile model that has a 1: 1 relationship with Profileuser.

How do I sort user models by skill_note_reputation values?

    user_list = User.objects.all ()

Thanks for letting me know how to fix it

Answer 1

If you add the parent_link=True key to your OneToOneField , you can reference fields in the Profileuser as if they belonged to the User model.

For example:

class Profileuser(models.Model):
    user = models.OneToOneField(
          User, on_delete=models.CASCADE,
          related_name='profileuser', parent_link=True)
    skill_note_reputation = models.IntegerField()

Now, you can filter your User model like this:

User.objects.filter(skill_note_reputation=1)

For a more pythonic approach, you can take advantage of Django's model inheritance , and turn your Profileuser model into this:

class Profileuser(User):
    skill_note_reputation = models.IntegerField()

Note that this model and the above model are identical.

If for some reason you don't want to do use parent_link=True , you can reference any ForeignKey columns using Django's LOOKUP_SEP , like this:

User.objects.filter(profileuser__skill_note_reputation=1)