保存每个 for 循环迭代的 output 以拆分嵌套列表

Question

I have a list of lists that looks like this mylst

[[('Salmon', 9), ('Fish&Chips', 3), ('Pasta', 8), ('Shrimp', 10)],
 [('Shrimp', 8), ('Fish&Chips', 10), ('Salmon', 9), ('Pasta', 7)],
 [('Shrimp', 10), ('Fish&Chips', 6), ('Salmon', 8), ('Pasta', 5)],
 [('Shrimp', 7), ('Pasta', 9), ('Salmon', 8), ('Fish&Chips', 8)],
 [('Fish&Chips', 10), ('Shrimp', 8), ('Salmon', 9), ('Pasta', 3)]]

I can access the sublists if I print the desired index

mylst[0]

which returns

[('Salmon', 9), ('Fish&Chips', 3), ('Pasta', 8), ('Shrimp', 10)]

But I would like to store each sublist in a new list.

Because eventually I would like to extract the items(tuple index 0) and the quantity ordered (tuple index 1) for each sublist and store them in two separate lists. But I can't do this if I can't split the lists

I tried to iterate through the main list

newlst=[]

for sublst in mylst:
    newlst.append(sublst)

and

newlst=[]

for i in range(len(mylst)):
    for sublst in mylst:
        newlst.append(mylst[i])

I am not sure how to split then store multiple outputs from each iteration of the for loop.

The desired output is to have the 5 sublists as seperate lists. For example

lst1=[('Salmon', 9), ('Fish&Chips', 3), ('Pasta', 8), ('Shrimp', 10)]

lst2 = [('Shrimp', 8), ('Fish&Chips', 10), ('Salmon', 9), ('Pasta', 7)]

and so on.

note: my question is not duplicate of this one , as I have read the solutions. I want to store my sublists in seperate lists. which is different.

Answer 1

If you just want to unpack the list then you can do what Chris said above and just do a,b,c,d,e = mylst , but if what you want is to repackage the data in a more usable way, then I suggest storing this in a pandas dataframe. You can do that with the following code

import numpy as np
import pandas as pd

my_df = pd.DataFrame(np.array(mylst).reshape(-1, 2),
    columns=['item', 'quantity']) 

Answer 2

You can make one massive nested list by using a for loop each containing the desired list.

for each in lst:
seplist = [] #splitted list of each digit of every integer
for eachagain in str(each):
    seplist.append(integer)
nestedlist.append(seplist)

Here the nested list can be separated and stored by using another for loop