我想用 Java 代码在浏览器上打开链接或 URL

Question

I have a URL(like: " https://www.google.co.in/ ") that should be open on browser(on same browser where my application is running.) at run time from Java code.

Searched many thing and found below java code but it's not working for me.

Desktop desktop = java.awt.Desktop.getDesktop();
URI uri = new URI(String.valueOf("My_Url"));
desktop.browse(uri);

While using above code, i am getting below exception

java.awt.HeadlessException
    at java.awt.Desktop.getDesktop(Desktop.java:142)

Also i have added and tried with below line of code with static block and without static block and getting same exception. Please suggest.

System.setProperty("java.awt.headless", "true");

Answer 1

use ProcessBuilder

    List<String> list = new ArrayList<String>(); 
    list.add("start"); 
    list.add("www.google.com");
    ProcessBuilder build = new ProcessBuilder(list);
    build.start();

Answer 2

Perhaps this will work?

String url = "http://www.google.co.in";

        if(Desktop.isDesktopSupported()){
            Desktop desktop = Desktop.getDesktop();
            try {
                desktop.browse(new URI(url));
            } catch (IOException | URISyntaxException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }else{
            Runtime runtime = Runtime.getRuntime();
            try {
                runtime.exec("xdg-open " + url);
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }

Answer 3

You can use Selenium Web Driver for opening a website into browser. click here to see web driver setup how to setup

import org.openqa.selenium.WebDriver;
import org.openqa.selenium.firefox.FirefoxDriver;

public class OpenSite
{
    public static void main(String[] args) throws Exception
    {
        WebDriver driver=new FirefoxDriver();
        // tries to open https://google.com
        driver.get("https://google.com");
    }
}