在 csv - awk 和 for 循环上使用 bash 脚本

Question

I have csv file for every day in a month, and the csv file has global point data. I am trying to crop each csv based on latitudinal and longitudinal extents, and export those csvs. Here is what I tried for 5 days in a month.

for f in ./VBD_npp_d20190[1-5]*.csv; do 
    awk '{for(i=$4>=3.070359 && i=$4<=40.926137 && i=$5>=107.159444 && i=$5<=128.204291){printf "%s ",$i;} print ""}' "$f" > "$f".new;
done

This dd not work. $4 and $5 columns have the latitudes and longitudes listed.

Please advise where I am going wrong.

Thanks,

Tilo

Answer 1

Trying to do it with a "for"? Interesting approach, but not what I'd have ever come up with. Much easier to us one (or more if statements)

pseudo code

{
    if ($4 > minLat && $4 < maxLat && $5 > minLon && $5 < maxLon)
    {
        print
    }
}

edit: in fact looks like you might have just a typo for instead of if ? (not quite, you'd remove the redundant i= bits and change the print

for f in ./VBD_npp_d20190[1-5]*.csv; do 
    # TODO: Modify the print to use $4 (and $5 ?) instead of $i
    awk '{if($4>=3.070359 && $4<=40.926137 && $5>=107.159444 && $5<=128.204291){printf "%s ",$i;} print ""}' "$f" > "$f".new;
done

Answer 2

This finally worked -

for i in./VBD_npp_d201901*_global*.csv;do o= basename $i global_noaa_ops_v23.csv china_noaa_ops_v23.csv; head -1 $i > $o; awk -F, '{if ($4>=3.07 && $4<=40.93 && $5>=107.16 && $5<=128.20) print;}' $i>> $o;done