如何打印列表的所有元素，而不仅仅是最后一个？

Question

I wrote a script that allows me to extract through a loop all the floating numbers and put them in a list, then display this list with all the extracted floating numbers except that in my script only the last number of each list is taken into account, while I would like all the numbers to be displayed. how to do it?

there is my code:

final_result = []
result = []
k = listFps
k = 0

while k < len(listFps):
    with open(listFps[k], 'r') as f:
        #
        statList = f.readlines()
        statList = [x.strip() for x in statList]
        for line in statList:
            if (re.search("=", str(line))):
                if (re.search('#IND', str(line))):
                    print("ok")
                else:
                    result =re.findall("=\s*?(\d+\.\d+|\d+)", str(line))

                    print (" ca c result " ,result)

     numberList = [float(q) for q in result]
     print("ca c number list :",numberList)

     k+=1

its print me only the last element of my list like this:

[59.889]
[60.874]

etc.. But i actually want a list with all element:

[59.889,60.874....]

Help me please im stuck with it for too long..

Answer 1

Instead of

result = re.findall….

use

result += re.findall…