[英]Small Issue with C program to convert lowercase to uppercase for stdout
I am learning about system calls in linux and I wrote a quick program to copy stdin to stdout.我正在学习 linux 中的系统调用,我编写了一个快速程序来将标准输入复制到标准输出。
I want to convert the stdin lowercase letters to uppercase letters before they are written.我想在它们被写入之前将标准输入小写字母转换为大写字母。
I implemented a function with a pointer to the array to capitalize the characters.我用指向数组的指针实现了一个 function 以大写字符。 It only capitalizes the first letter of the write though and I don't understand why.它只大写写的第一个字母,我不明白为什么。 From what I understand, I wouldn't need a for loop because of the read() system call.据我了解,由于 read() 系统调用,我不需要 for 循环。
#include <unistd.h>
#define SIZE 512
char charToUpper(char *);
int main () {
int nread;
char buf[SIZE];
while (nread = read(0, buf , SIZE)) {
charToUpper(buf);
write(1,buf,nread);
}
return 0;
}
char charToUpper(char *a){
if ((*a > 96) && (*a <123)) {
*a = *a-32;
return *a;
}
}
Your charToUpper
receives a pointer to a char
, and you sent it buf
, which decays to a pointer to a char
of the first character in buf
, hence your result.您的charToUpper
收到一个指向char
的指针,然后您将其发送到buf
,该指针衰减为指向buf
中第一个字符的char
的指针,因此是您的结果。
Remember in c
you do not get the size of the array you are passing for free - you have to pass it on as well.请记住,在c
中,您不会免费获得要传递的数组的大小 - 您也必须传递它。 Consider all your operations in charToUpper
are on *a
, which is of type char
, a single character.考虑您在charToUpper
中的所有操作都在*a
上,它是char
类型,一个单个字符。 So to fix this change the declaration to因此,要解决此问题,请将声明更改为
char charToUpper(char *, unsigned int size);
so know you know how many characters you actually read and need to change.所以知道你知道你实际阅读了多少个字符并且需要更改。 Try and change your program now to suit this.现在尝试更改您的程序以适应这种情况。 One hint - your return
will probably have to move for example.一个提示 - 例如,您的return
可能必须移动。
he program is perfectly fine except for the loop part.除了循环部分外,他的程序非常好。
char* charToUpper(char *a){
char *t=p;
while(*a!='\0'){
if ((*a > 96) && (*a <123))
*a = *a-32;
a++;
}
return t;
}
you didn't incremented the loop.你没有增加循环。 do it and u will get去做,你会得到
The following proposed code:以下建议的代码:
toupper()
from the header file: ctype.h
使用工具将所有小写字符正确更改为大写: toupper()
来自 header 文件: ctype.h
and now, the proposed code:现在,建议的代码:
#include <unistd.h>
#include <ctype.h> // toupper()
#define SIZE 512
void charToUpper(char *);
int main ( void )
{
ssize_t nread;
char buf[SIZE];
while ( (nread = read(0, buf , SIZE) ) > 0)
{
// NUL terminate the character string
buf[nread] = '\0';
// convert all characters to uppercase
charToUpper(buf);
// output the (all uppercase) string to stdout
write(1,buf, (size_t)nread);
}
return 0;
}
void charToUpper( char buf[] )
{
for( size_t i = 0; buf[i]; i++ )
{
buf[i] = (char)toupper( buf[i] );
}
}
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