从 oracle 中的 clob 列中提取数据

Question

I am having data in clob column as below:

:1A:CAD22021828,17
:1B:RECEIVE GENERAL IND
11 BEGUM ST 3-15A2
  VILL              AP IND 313 416
:1C:/000061071257      CC
RECEIVER GENERAL FOR IND
C/O PNBB MAIN BRANCH
11 BEGUM ST 3-15A2
AA HYD         APIND

Now my requirement is to load this into 3 separate columns in target table as below:

1A    - CAD22021828,17
1B    - RECEIVE GENERAL IND 
        11 BEGUM ST 3-15A2
        VILL              AP IND 313 416
1C    - /000061071257      CC
        RECEIVER GENERAL FOR IND
        C/O PNBB MAIN BRANCH
        11 BEGUM ST 3-15A2
        AA HYD         APIND

can someone suggest how I can do this.

This is oracle 11.2

I have tried below code;

SELECT
    REGEXP_SUBSTR(mc_clob,':1A:([[:alnum:]]+\S+)') AS code1A,
    REGEXP_SUBSTR(mc_clob,':1B:([[:alnum:]]+\s+)') AS code1B,
    REGEXP_SUBSTR(mc_clob,':1C:([[:alnum:]]+\s+)') AS code1c
FROM tableA;

Answer 1

Here is one way to do this using REGEXP_SUBSTR with capture groups:

SELECT
    REGEXP_SUBSTR(mc_clob, ':1A:(.*):1B:', 1, 1, 'n', 1) AS code1A,
    REGEXP_SUBSTR(mc_clob,':1B:(.*):1C:', 1, 1, 'n', 1) AS code1B,
    REGEXP_SUBSTR(mc_clob,':1C:(.*)', 1, 1, 'n', 1) AS code1c
FROM tableA;

Demo

To understand how this works, take the first call to REGEXP_SUBSTR :

REGEXP_SUBSTR(mc_clob, ':1A:(.*):1B:', 1, 1, 'n', 1)

This says to match :1A:(.*):1B: , capturing all content between the :1A: and :1B: markers. The fifth parameter is n , which tells Oracle to let dot match across newlines. That is, (.*) will capture all content between the two markers, including across lines. The sixth parameter is 1 , which means that the return value will be the first (and only) capture group. Similar logic applies to the second and third call to REGEXP_SUBSTR .