Python 随机使用 if 语句

Question

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I tried making a sort of text-based game: but I haven't been able to get the first part to work - as it seems to ignore the statement qualifier and does the statement anyway or at least repeats it. Help would be most appreciated. Ignore the odds they are place holders.

import random
import math
php=30
while php>0:
    r=random.randint(1,10)
    if r==7:
        print("Found a room with a chest")
        o=input("do you open it?(Y/N)")
        t=random.randint(1,20)

        if o=="Y":
            l=random.randint(1,2)
            lq=random.randint(1,8)
            print(l,"item")
            print(lq,"quality")
            if l==1:
                item="weapon"
            if l==2:
                item="armour"

            if lq == 1 or 2:
                q="bad"
                print(lq,q)
                if item =="weapon":
                    d=random.randint(0,2)
                    dice=4
                    print(q)
                    print(random.randint(1,dice)+random.randint(1,dice)+d)

                if item =="health":
                    armour=random.randint(1,3)

            if lq == 3 or 4 or 5 or 6 or 7:
                q="good"
                print(lq,q)
                if item =="weapon":
                    da=random.randint(1,3)
                    dice=6
                    print(q)
                    print(random.randint(1,dice)+random.randint(1,dice)+d)

                if item =="armour":
                    armour=random.randint(2,6)

            if lq == 8:
                q="rare"
                print(lq,q)
                if item =="weapon":
                    d=random.randint(2,5)
                    dice=random.randint(6,8)
                    print(q)
                    print(random.randint(1,dice)+random.randint(1,dice)+d)

                if item =="armour":
                    armour=random.randint(4,8)
                ```

Answer 1

The problem is that there are places where you are not evaluating anything that could be falsey in some of your if statements.

For example, you have this line:

if lq == 3 or 4 or 5 or 6 or 7

The values of 4 , 5 , 6 , and 7 are not expressions to evaluate; they are simply values, which causes python to enter the if block.

Instead, you will need to either break out the or statements into expressions to evaluate:

if lq == 3 or lq == 4 or lq == 5 or lq == 6 or lq == 7

Or, the more pythonic way, is to make use of in to check if a value is in a list ( in can evaluate types other than a list, but that's not important right now). You would do it like this:

if lq in [3, 4, 5, 6, 7]

Edit: Axiumin_ pointed out that this scenario of checking if your value is within a range (as opposed to discrete values) can be evaluated as simply as:

if lq >= 3 and lq <= 7

Another pythonic and simple way to evaluate a range, is to use the range function:

if lq in range(3, 7)