初始化整数列表。 解释器返回“ValueError: invalid litteral for int()”

Question

Trying to make a list of ints the user inputs. Inerpreter is returning "ValueError: invalid literal for int() with base 10:"

I'm somewhat new to python and I'm practicing on a website called "geeks for geeks". Link to the problem I'm working on here The goal of the exercise is to print the first negative integer in a sub array of user specified size. When I try to append the user inputs to the list, the interpreter is giving me a value error. It's obviously not a type error but I can't figure out what kind of input could be given to the program to give it that error. The inputs are on a file on geeks for geek's servers so I can only test on inputs I've made.

# This file is for a programing practice exercise of geeksforgeerks.org
# The exercise is first negative int in window of size k

# selecting number of test cases
T = int(input())
for t in range(T):
    # initializing array
    n = int(input())
    arr = []
    while n > 0:
        arr.append(int(input().strip()))
        n-=1
    k = int(input())
    win = 0 # index of first element in widow subarray
    # terminate loop when the window can't extend further
    while win < len(array) - k -1:
        # boolean for no negatives found
        noNeg = True
        for i in range(win, k):
            if arr[i] < 0:
                print(arr[i])
                noNeg = False
                break
            elif i == k-1 and noNeg:
                # 0 if last sub arr index reached and found no negs
                print(0)
        win+=1

The interpreter is giving the following error on line 11:

print(int(input().strip()))
ValueError: invalid literal for int() with base 10: '-8 2 3 -6 10'

Answer 1

The input data contains multiple numbers on the same line. input() returns a whole line of input, and when you call int(input().strip()) you're trying to parse that whole line as a single number.

You need to split it at whitespace. So instead of a while loop, you can use:

arr = map(int, input().strip().split())

Answer 2

Looks like you're inputting multiple integers, int() won't know how to convert them - it expects a single integer to be contained in the string. You'll want to split up the string and then convert:

Ts = [int(word) for word in input().strip().split(" ")]

Note that this will give you a list instead of a single integer.

Answer 3

you are feeding the input with multiple integers, you can extend your array at line 11 with your desired values:

arr = []
arr.extend(map(int, input().strip().split()))
# input: -8 2 3 -6 10

output:

[-8, 2, 3, -6, 10]