从 textarea 中删除换行符和分段符

Question

I am trying to 'flatten' (removing line breaks and paragraph breaks) from any given input from a textarea.

Suppose the input is:

select * where { 
    ?s ?p ?o .
} limit 100 

The expected outcome is:

select * where { ?s ?p ?o . } limit 100 

So far I have managed to remove the line breaks using the following piece of code:

val.replace(/$(\r|\n)(?=.)/gm, ' ');

Which is currently giving me:

select * where {    ?s ?p ?o . } limit 100

Any thoughts? Thanks in advance!

Answer 1

I'd suggest

val = val.replace(/[^\S\r\n]*[\r\n]+\s*/g, ' ')

This will "shrink" linebreaks (including any consecutive blank lines) with adjacent whitespaces into a single space char.

Here,

• [^\S\r\n]* - matches 0+ horizontal spaces
• [\r\n]+ - 1+ CR or LF chars
• \s* - any 0+ whitespce chars.

See the regex demo .

Answer 2

About CRLF:
- As @Unimportant suggests, replace \s+ with space.
Reason is that formatting the result won't work anyway it's done.
Better to be consistent with even looking separation.

About Paragraph breaks and Breaks:
- Would be replace </?p\s*>|<br\s*/> with nothing.

So, 2 separate regex run independent of each other would do the job.

Answer 3

Add the space character \s to your match criteria, and also add a * to signify that there can be more than one concurrent match. From here you'll simply want to replace such characters with an empty string instead of a space.

This can be seen in the following:

 const val = `select * where {?s?p?o. } limit 100 `; console.log(val.replace(/$(\r|\n|\s)*(?=.)/gm, ''));