java 懒惰 stream 构造中的问题

Question

I was looking at this link for lazy stream construction and tried using it for one of my cases.

My primary stream has some operations that are needed to be done on Stream.onClose() .

In my custom logic, I use Iterator from Stream.iterator() for stream processing.

This worked fine consuming the actual Stream. But, when I used Stream.flatMap() for constructing a lazy stream, onClose function gets called when I start iterating, which in-turn creates problems for me.

I tried this in zulu-opendjk 1.8.0_222 and 13. I am facing this exception in both the environments.

You can reproduce the problem with the below code.

import java.util.*;
import java.util.stream.Stream;
import java.util.stream.StreamSupport;

public class TestStreamIterator
{
    public static void main(String args[])
    {
        Stream<String> stream1 = getStream();
        stream1.iterator().forEachRemaining(System.out::println);

        Stream<String> stream2 = Stream.of(1).flatMap(integer -> getStream());
        stream2.iterator().forEachRemaining(System.out::println);
    }

    private static Stream<String> getStream()
    {
        List<String> values = Arrays.asList("a", "b", "c");

        MyIterator iterator = new MyIterator(values);
        Stream<String> stream = StreamSupport.stream(Spliterators.spliteratorUnknownSize(iterator, Spliterator.NONNULL | Spliterator.IMMUTABLE), false).onClose(iterator::close);

        return stream;
    }

    private static class MyIterator implements Iterator<String>, AutoCloseable
    {
        private Iterator<String> iterator;

        public MyIterator(List<String> values)
        {
            iterator = values.iterator();
        }

        @Override
        public boolean hasNext()
        {
            return iterator.hasNext();
        }

        @Override
        public String next()
        {
            return iterator.next();
        }

        @Override
        public void close()
        {
            throw new IllegalStateException("Should not come here");
        }
    }
}

My understating is, when using flatMap ; close method of Stream.of(1) only should be called. Not of the stream created inside flatMap function.

I was expecting the onClose function to be invoked only when the stream is closed. But, I am not sure where the stream is getting closed.

Any help on solving this case would also be helpful.

Answer 1

When you call flatMap(integer -> getStream()) here:

Stream<String> stream2 = Stream.of(1).flatMap(integer -> getStream());
stream2.iterator().forEachRemaining(System.out::println);

You are calling this method:

Iterator

<R> Stream<R> flatMap(Function<? super T, ? extends Stream<? extends R>> mapper);

Returns a stream consisting of the results of replacing each element of this stream with the contents of a mapped stream produced by applying the provided mapping function to each element. Each mapped stream is closed after its contents have been placed into this stream . (If a mapped stream is null an empty stream is used, instead.)

So as the documentation says, the mapped stream you pass into this method (from getStream() which is a Stream over a MyIterator ) will be closed, which it is, then (as defined in onClose of that Stream) it calls MyIterator.close() which throws the exception.

---

Addressing your comment since you don't seem to follow:

Stream<String> stream2 = Stream.of(1).flatMap(integer -> getStream());

Creates a stream that will lazily map to the contents of a sub-stream when you read it. When that sub-stream is loaded into the main stream the sub-stream will be closed.

stream2.iterator().forEachRemaining(System.out::println);

You read from the main stream, which maps to the sub-stream, which reads all the sub-stream then closes the sub-stream which then calls Stream.onClose() which calls MyIterator.close()