[英]How to I validate so the user only enters integers
Iv'e been trying to get my code to work so that the user can only input integers.我一直试图让我的代码工作,以便用户只能输入整数。 However, its keeps crashing when I enter something with characters like "awsd".但是,当我输入带有“awsd”等字符的内容时,它会一直崩溃。 I've tried using a bool to help, but it only catches negative inputs.我尝试使用 bool 来提供帮助,但它只捕获负面输入。 Also, the input method must start as an integer, so I cant switch it to a string.此外,输入法必须以 integer 开头,所以我无法将其切换为字符串。 Please help.请帮忙。
import java.util.Scanner; // Needed for Scanner class
import java.io.*; // Needed for File I/O classes
public class Reverse {
public static void main(String[] args) throws IOException {
Scanner keyboard = new Scanner(System.in);
String Continue = "yes";
int num;
//creates the file name
File fileWR = new File("outDataFile.txt");
//creates the file object
fileWR.createNewFile();
//file scanner
BufferedWriter output = new BufferedWriter(new FileWriter(fileWR, true));
while (Continue.equals("yes")) {
System.out.print("Enter an integer number greater than 0 :");
num = keyboard.nextInt();
keyboard.nextLine();
if (fileWR.exists())
{
validate(num, output);
}
else
{
fileWR.createNewFile();
}
//option if the user wants to continue
System.out.println("Do you wish to continue?(yes or no): ");
Continue = keyboard.nextLine();
}
output.close();
}
public static void validate(int num, BufferedWriter output) throws IOException {
Scanner keyboard = new Scanner(System.in);
while(!checkNum(num))
{
System.out.print("That is not an integer greater than 0, please try again: ");
num = keyboard.nextInt();
keyboard.nextLine();
}
System.out.print("The original numbers are " + num +"\n");
output.write("\r\nThe original numbers are " + num +"\r\n");
reverse (num, output);
even (num, output);
odd(num, output);
}// end of public static void validate
public static void reverse(int num, BufferedWriter output) throws IOException {
String input = String.valueOf(num); //must output result within the void method for it to count as a void method
String result = ""; //otherwise, you cannot output it in the main method.
for (int i = (input.length() - 1); i >= 0; i--)
{
result = result + input.charAt(i)+' ';
}
result = "the number reversed "+ result +"\r\n";
System.out.print(result);
output.write(result);
}// end of public static void reverse
public static void even(int num, BufferedWriter output) throws IOException {
String input = String.valueOf(num);
String result = "";
for (int i = 0; (i < input.length()); i++)
{
if (Character.getNumericValue(input.charAt(i)) % 2 == 0)
result = result + input.charAt(i) + ' ';
}
if (result == "") {
result = "There are no even digits" + "\r\n";
} else {
result = "the even digits are "+ result +"\r\n";
}
System.out.print(result);
output.write(result);
}// end of public static void even
public static void odd(int num, BufferedWriter output) throws IOException {
String input = String.valueOf(num);
String result = "";
for (int i = 0; (i < input.length()); i++)
{
if (Character.getNumericValue(input.charAt(i)) % 2 == 1)
{
result = result + input.charAt(i) + ' ';
}
}
if (result == "") {
result = "There are no odd digits" + "\r\n";
} else {
result = "the even odd digits are "+ result +"\r\n";
}
System.out.print(result);
output.write(result);
System.out.print("------------------------\n");
output.write("------------------------\n");
}// end of public static void odd
public static boolean checkNum(int num)
{
if(num > 0) {
return true;
}
else {
return false;
}
}
}
You should first get the String, and then try to cast it:您应该首先获取字符串,然后尝试转换它:
try {
String numStr = keyboard.nextLine();
num = Integer.parseInt(numStr);
//Complete with your code
} catch (NumberFormatException ex) {
System.out.print("That is not an integer");
}
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