我在通过 Hibernate 从数据库中获取准确值时遇到问题

Question

I want to search by Hibernate search and get fields of the table which fields equals to value of search parameter not like how it does search

I have a field which I search

@Field(name = "field", analyzer = @Analyzer(definition = "whitespaceAnalyzer"))
private String field;

and I search it by creating this query

queryBuilder.keyword().onField("field").matching("value").createQuery()

But it searches by like operator not equal I know that if I write

@Field(name = "field", analyzer = Analyze.NO)

It will work but I want to let @Field annotation in this way and search field by equal operator How can I do it in my case.

Answer 1

You can make use of

javax.persistence.criteria.CriteriaBuilder

    CriteriaBuilder criteriaBuilder = entityDAO.getCriteriaBuilder();
    CriteriaQuery<?> criteriaQuery = criteriaBuilder.createQuery(Field_className.class);

    Root<Field_className> entity = criteriaQuery.from(Field_className.class);
    criteriaQuery.where(criteriaBuilder.equal(entity.get("field"),identifier));
    Field_className = (Field_className)entityDAO.createQuery(criteriaQuery).getSingleResult();

Please note replace Field_className with your className