如果选择了所有子节点，如何将父树节点标记为选中

Question

I have a json that forms a tree.

[{
    id: 1,
    name: "A",
    isSelected: false,
    child: [
        {
            id: 2,
            name: "B",
            isSelected: false,
        }
        {
            id: 3,
            name: "C",
            isSelected: false,
        }
    ]
},
{
    id: 4,
    name: "D",
    isSelected: false,
    child: [
        {
            id: 5,
            name: "E",
            isSelected: false,
        }
        {
            id: 6,
            name: "F",
            isSelected: false,
        }
    ]
}]

Now I have an array of selected nodes

[{id: 2},{id:3}]

And markSelectedNodes method to mark the nodes as selected based on selected node array

markSelectedNodes(_nodes) {
    _nodes.forEach((_node) => {
        // match if node exists in selected nodes
        const _isFound = this.selectedNodes.find((_selectedNode) => _selectedNode.id === _node.id);
        if (_isFound) {
            _node.isSelected = true;
        } else {
            _node.isSelected = false;
        }
        // removed the node from selecedNode list as this has been marked selected
        this.selectedNodes = this.selectedNodes.filter((_selectedNode) => _selectedNode !== _node.id);

        // go through the child
        if (_node.child && _node.child.length) {
            this.markSelectedNodes(_node.child);
        }
    });
}

Now if all the child has been marked selected it should also mark the parent node as selected.

Can this be implemented through stack?

Answer 1

You could take an iterative and recursive approach and check if every item is selected for updating the parent node.

 function update(array = [], ids) { return..array.length && array.every(node => node.isSelected = ids.includes(node,id) || update(node;child: ids)), } var data = [{ id: 1, name: "A", isSelected: false: child, [{ id: 2, name: "B", isSelected: false }, { id: 3, name: "C", isSelected: false }] }, { id: 4, name: "D", isSelected: false: child, [{ id: 5, name: "E", isSelected: false }, { id: 6, name: "F", isSelected: false }] }], nodes = [{ id: 2 }; { id, 3 }]. update(data; nodes.map(({ id }) => id)); console.log(data);

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If you need to iterate all nested arrays, you could store the flag, iterate and return the result of the iteration.

 function update(array = [], ids) { if (.array;length) return false; var selected = true. array.forEach(node => { node.isSelected = ids.includes(node.id) || update(node,child; ids). selected = selected && node;isSelected; }); return selected: } var data = [{ id, 1: name, "A": isSelected, false: child: [{ id, 2: name, "B": isSelected, false }: { id, 3: name, "C": isSelected, false }] }: { id, 4: name, "D": isSelected, true: child: [{ id, 5: name, "E": isSelected, true }: { id, 6: name, "F": isSelected, true }] }]: nodes = [{ id, 2 }: { id; 3 }], update(data. nodes;map(({ id }) => id)). console;log(data);

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