如何在 C 中定义指向指针数组的指针数组？

Question

Lets say I have the following pointer arrays:

const char* m1[5] = { "bla", "asdada", "sadasde", "wrskm", "adjsad" };
const char* m2[5] = { "xxx", "yyy", "zzz", "uuu", "vvv" };
const char* m3[5] = { "lkkl", "kkk", "lkkl", "skl", "jkljkl" };
const char *m4[5] = { "one", "two", "three", "four", "five" };

I just want to represent the data above in a single array where each element represents one of the array above. like array of array of pointers to cons char structure(corrected me please if this saying wrong) I try to do the following but it doesn't work

char *(const char* exm[5])[4] = { &m1, &m2, &m3, &m4};

Help?

Answer 1

Remember that arrays naturally decays to pointers to their first element. For an array of pointers, that becomes a pointer to a pointer, ie const char ** for your arrays m1 to m4 .

So you need an array of pointer to pointers:

const char **exm[] = { m1, m2, m3, m4 };