如何防止 function 被其他捆绑包 id 调用

Question

can I restrict function call by bundle id

For example I have created extension for string

 extension String {
        func trim() -> String {
        if let bundle = Bundle.main.bundleIdentifier {
            if bundle.hasPrefix("xyz") {
                return self.trimmingCharacters(in: .whitespacesAndNewlines)
            }
            else {
                print("Framework Restricted")
                return  ""
            }
        }
    }
}

It gives error at runtime but i want prevent user to access the trim() funtions at compile time remember source is not visible to user it's static framework

Issue: I have too many function so i have to put condition in all of the istead i want to code something to make it easy.

Answer 1

Since frameworks are precompiled, you can't have a compile time error. You should have a runtime error.

Make a global function and call it where ever you need:

func crashIfStolen() {
    if Bundle.main.bundleIdentifier != myBundle {
        fatalError("Unauthorized use of the framework")
    }
}

NSObject has a method called load that automatically gets called on load of the framework (just by being in the app).

class X: NSObject {
    override class func load() {
        crashIfStolen()
    }
}

But

Method 'load()' defines Objective-C class method 'load', which is not permitted by Swift.

So you can have an Objective-C class in your framework with this function to make it dynamically restricted. (Swift is static)