[英]Logstash grok filter apache pattern
This is a sample Apache Tomcat log:这是一个示例 Apache Tomcat 日志:
portal.portal.some.thing.int:8443 13.233.220.113 - - [09/Sep/2019:00:08:02 +0200] "GET /en/search-results?p_p_id=portal201_WAR_portal201_INSTANCE_q8EzsBteHybf&p_p_lifecycle=1&p_p_state=normal&queryText=Poll&facet.collection=AΜLex%2CAMsom%2CAMss%2WebPage%2SummariesOfSomething&startRow=1&resultsPerPage=10&SEARCH_TYPE=SIMPLE HTTP/1.1" 230 334734 6261 - - 35S64857F6860FDFC0F60B5B47A97E18
10.235.350.103 94.62.15.157, 10.435.230.101,10.134.046.2
I would like to capture the following variables我想捕获以下变量
09/Sep/2019:00:08:02 +0200 2019 年 9 月 9 日:00:08:02 +0200
/en/search-results?p_p_id=portal2.... /en/search-results?p_p_id=portal2....
35S64857F6860FDFC0F60B5B47A97E18 35S64857F6860FFC0F60B5B47A97E18
Can you help me with that?你能帮我解决这个问题吗? I want to index only those and drop the others, is it possible?
我只想索引那些并删除其他的,这可能吗? Thank you
谢谢
Use this grok pattern:使用这个 grok 模式:
%{GREEDYDATA:field1} %{IP:ip1} - - \[%{GREEDYDATA:date}] \"%{WORD:method} %{GREEDYDATA:request}" %{WORD:numbers} %{WORD:numbers} %{WORD:numbers} - - %{WORD:last_parameter}
input:输入:
portal.portal.some.thing.int:8443 13.233.220.113 - - [09/Sep/2019:00:08:02 +0200] "GET /en/search-results?p_p_id=portal201_WAR_portal201_INSTANCE_q8EzsBteHybf&p_p_lifecycle=1&p_p_state=normal&queryText=Poll&facet.collection=AΜLex%2CAMsom%2CAMss%2WebPage%2SummariesOfSomething&startRow=1&resultsPerPage=10&SEARCH_TYPE=SIMPLE HTTP/1.1" 230 334734 6261 - - 35S64857F6860FDFC0F60B5B47A97E18
10.235.350.103 94.62.15.157, 10.435.230.101,10.134.046.2
output: output:
{
"field1": [
[
"portal.portal.some.thing.int:8443"
]
],
"ip1": [
[
"13.233.220.113"
]
],
"IPV6": [
[
null
]
],
"IPV4": [
[
"13.233.220.113"
]
],
"date": [
[
"09/Sep/2019:00:08:02 +0200"
]
],
"method": [
[
"GET"
]
],
"request": [
[
"/en/search-results?p_p_id=portal201_WAR_portal201_INSTANCE_q8EzsBteHybf&p_p_lifecycle=1&p_p_state=normal&queryText=Poll&facet.collection=AΜLex%2CAMsom%2CAMss%2WebPage%2SummariesOfSomething&startRow=1&resultsPerPage=10&SEARCH_TYPE=SIMPLE HTTP/1.1"
]
],
"numbers": [
[
"230",
"334734",
"6261"
]
],
"last_parameter": [
[
"35S64857F6860FDFC0F60B5B47A97E18"
]
]
}
fields you want are:你想要的领域是:
You can remove other fields using remove field in mutate filter.您可以使用 mutate 过滤器中的remove field删除其他字段。
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