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如何从列表中获取具有频率的唯一值<string[]>在 Java 中?</string[]>

[英]How to get unique values with frequency from List<String[]> in Java?

I want to get unique values from a List<String[]> and store them in a new list (or HashMap<String, Integer> where String is the unique value and Integer is its number of occurrences in the List<String[]> . How can I extract the unique values?我想从List<String[]>获取唯一值并将它们存储在一个新列表中(或HashMap<String, Integer>其中String是唯一值, Integer是它在List<String[]>中的出现次数. 如何提取唯一值?

You can use Collectors.groupingBy您可以使用Collectors.groupingBy

Map<String, Long> map = abc.stream()
                           .flatMap(Arrays::stream)
                           .collect(Collectors.groupingBy(Function.identity(),
                                       Collectors.counting()));

If you are using Java 8 or above it's pretty easy.如果您使用的是 Java 8 或更高版本,这很容易。 (Slight correction using the other answer) (使用其他答案进行轻微修正)

List<String[]> abc = new ArrayList<>();
String[] string1 = {"123", "567"};
String[] string2 = {"123", "456"};
abc.add(string1);
abc.add(string2);

List<String> newList = abc.stream()
        .flatMap(Arrays::stream)
        .distinct()
        .collect(Collectors.toList());

Map<String, Long> hashMap = abc.stream()
            .flatMap(Arrays::stream)
            .collect(Collectors.groupingBy(Function.identity(), Collectors.counting()));

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