如何使用 Powershell 在没有 Mode、LastWrite 等的情况下导出 CSV 文件中的目录文件？

Question

Using dir > list.csv will create the list I need in whichever directory im in, but it includes unnecessary information as well. It has a column for the Mode, LastWriteTime, LengthName etc which I then have to manually delete, because I'm using OpenOffice and need the list of files to compose a new CSV which I'm then going to import into a database.

I would like to use a switch that allow me to solely export the file name in CSV not the other items. Is this possible with a useful command or switch or would it involve scripting?

Answer 1

Do you mean this?

Get-ChildItem | Select-Object -ExpandProperty Name > list.txt

The list.txt will contain the filename of each file.

(Note that CSV means "comma-separated values" and is a delimited file format. A plain list of names really isn't a CSV file.)

Answer 2

Try this:

Get-ChildItem | Select-Object -ExpandProperty Name > test.csv 
(Get-Content test.csv) -join ',' | Set-Content test.csv