Google Apps 脚本从工作表中提取特定列并使用过滤器和 map 放入新工作表 — 慢

Question

Thanks in advance for your help. I'm new to apps script.

I have a gsheet with 98 columns and 25000 rows. All I want to do is copy 24 of the 98 columns to a new sheet.

Currently I am using filter & map, and it works:

var data = sourceSheet.getDataRange().getValues(); //read all columns & rows into array

var filterData = data.filter(function(e, j){return j > 0 && e}).map(function(e){return [e[88], e[14], e[13], e[4], e[17], e[87], e[91], e[48], e[57], e[31], e[89], e[82], e[70], e[97], e[47], e[30], e[72], e[71], e[67], e[34], e[33], e[00], e[38], e[39]]}); //extract just the columns I want into a new array

but that 2nd line takes almost an hour to execute, I presume because it is processing every element 1-by-1. even though it is just to return each one.

I haven't tried getValue'ing and setValue'ing columns one at a time because everything I read says limit external calls and do everything in memory. And I can't imagine pushing elements 1-by-1 would be faster than filtering.

Suggestions for faster execution?

Answer 1

function doCopy(SpreadID, OrgSheet, DestSheet, OrgRange, Sql, DestCell) { 
  var mySpread = SpreadsheetApp.openById(SpreadID);
  var myQry = '=QUERY(' + OrgSheet + "!" + OrgRange + ',\"'+ Sql + '\")';
  var myDestSheet = mySpread.getSheetByName(DestSheet);
  myDestSheet.getRange(DestCell).setFormula(myQry);
}

Sample to call, but the destination sheet must be blank:

doCopy(spreadsheetId,"Sheet1", "Sheet2", "A:G", "Select A, C, F", "A1");

Answer 2

Another way to look at the problem which might be more time-effective and easy to implement is the following:

1. Duplicate the original sheet into a new one with copyTo(spreadsheet) ( https://developers.google.com/apps-script/reference/spreadsheet/sheet#copytospreadsheet ). You might also want to check this post for more information about creating a sheet into the same spreadsheet ( Google Script to Duplicate Sheet that is Not Active )

2. Delete the columns you don't want to keep with deleteColumn(columnPosition) or deleteColumns(columnPosition, howMany) (see https://developers.google.com/apps-script/reference/spreadsheet/sheet#deletecolumncolumnposition ). You might also want to start deleting columns from the right side of the sheet to make the implementation easier.

Let me know if it helps.