有没有办法将 void (*)(uint32_t, void (*)(uint32_t)) 转换为 std::function <void(uint32_t, std::function<void(uint32_t)> )&gt;?</void(uint32_t,>

Question

I'd like to build a C++ library which is usable from C as well. This is the header file I want to be able to compile in C:

typedef void (*log_function_t)(const char *);
typedef void (*delay_function_callback_t)(uint32_t);
typedef void (*delay_function_t)(uint32_t, delay_function_callback_t);

extern "C" void core_init(log_function_t logFunction, delay_function_t delayFunction);

However, since I'm writing the library in C++, it would be nice to work with std::function objects instead of function pointers, so I'd like to call functions like this:

using LogFunction = std::function<void(const char*)>;
using DelayFunctionCallback = std::function<void(uint32_t)>;
using DelayFunction = std::function<void(uint32_t, DelayFunctionCallback)>;

void setLogFunction(const LogFunction& logFunction);
void setDelayFunction(const DelayFunction& delayFunction);

Calling the setLogFunction works just fine, but when I try to call setDelayFunction it doesn't work.

void core_init(log_function_t logFunction, delay_function_t delayFunction)
{
    Utility::getInstance().setLogFunction(logFunction);
    Utility::getInstance().setDelayFunction(delayFunction);
}

It says: Reference to type 'const DelayFunction' (aka 'const function<void (unsigned int, function<void (unsigned int)>)>') could not bind to an lvalue of type 'delay_function_t' (aka 'void(*)(unsigned int, void (*)(unsigned int))')

Obviously I understand why it doesn't work, but I have a feeling that it should be possible to solve and I'm just not experienced enough to solve it.

Answer 1

What you're asking seem to be passing a function pointer from C to C++ where the function takes a std::function as argument. I'm afraid this is not possible just as C can't pass a function pointer that takes a std::vector as argument.

When calling Utility::getInstance().setDelayFunction(delayFunction) , the ctor of a specialized std::function (ie DelayFunction ) is matched to construct from a function pointer. However, the match fails because the ctor (of DelayFunction ) accepts as its 2nd argument a specialized std::function (ie DelayFunctionCallback ), rather than a function pointer (ie delay_function_callback_t ).

I think the problem lies in the implementation of std::function , which encapsulates the function pointer and erases the latter's type. (See How is std::function implemented? ) As a result, a C++ std::function is a different type than a plain-C function pointer.

To workaround this, you could relax the C++-ishness a bit and declare DelayFunction as accepting void(*)(unsigned) instead. Ie, in the C++ file:

using LogFunction = std::function<void(const char*)>;
using DelayFunction = std::function<void(unsigned, delay_function_callback_t)>;
//                                                 ^^^^^^^^^^^^^^^^^^^^^^^^^

EDIT: Re. the comment on calling the DelayFunction object from C++, instead of passing a lamba function as the callback (which would fail with the workaround above, since the lambda function can only construct a DelayFunctionCallback , not a delay_function_callback_t ), it might be easier to implement the callback as a static member function and use it directly:

Utility::getInstance().delay(delay, (delay_function_callback_t)&Utility::next);

---

BTW, if Utility is going to store the std::function objects internally, then it may be more efficient to pass-by-value, since the LogFunction and DelayFunction objects will always be constructed anyway (ie they are rvalue in core_init ).

Answer 2

A void(*)() is fundamentally different from a std::function<void()> .

You can get closer with a void(*)( void* ), void* ; a std function has both callable-ness and state, a function pointer only has callable-ness. (std function also carries RTTI and how-to-cleanup-state and how-to-copy-state).

Now you can convert a void(*)() into a std function that is stronger; but not the other way. And the arguments to a function are converted the other way when the call happens.

struct callback {
  void* state;
  void(*action)(int32_t);
  void(*cleanup)(void*);
  void*(*copy)(void*);
};

that is the rough C equivalent of a std::function<void(int32_t)> .