检查字符串中是否存在值

Question

I have such string: 'Oracle Database Token: xxxx.';

I need to return true or false if xxxx is one of three variants:

• 1 or 11 or 111 or 1111 or 11111 or 111111 etc.
• character '-'
• number 123456789

I tried to build a regular expression for the regexp_substr() function but it turned out to be very hard.

Is this possible in a regular expression?

Answer 1

You can use TRANSLATE to test for the first condition and the other two are simple tests for equality:

SELECT *
FROM   your_table
WHERE  token = 'Oracle Database Token: -.'
OR     token = 'Oracle Database Token: 123456789.'
OR     (   token <> 'Oracle Database Token: .'
       AND TRANSLATE( token, '_1', '_' ) = 'Oracle Database Token: .' )

Sample Data :

CREATE TABLE your_table ( token ) AS
  SELECT 'Oracle Database Token: -.' FROM DUAL UNION ALL
  SELECT 'Oracle Database Token: 123456789.' FROM DUAL UNION ALL
  SELECT 'Oracle Database Token: 1.' FROM DUAL UNION ALL
  SELECT 'Oracle Database Token: 111.' FROM DUAL UNION ALL
  SELECT 'Oracle Database Token: 111111.' FROM DUAL UNION ALL
  SELECT 'Oracle Database Token: 12111.' FROM DUAL UNION ALL
  SELECT 'Oracle Database Token: -12.' FROM DUAL;

Query Output :

 |  TOKEN | |:-------------------------------- |  |  Oracle Database Token: -.  |  |  Oracle Database Token: 123456789. |  |  Oracle Database Token: 1. |  |  Oracle Database Token: 111. |  |  Oracle Database Token: 111111. | 

db<>fiddle here

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You could also write it as a regular expression:

SELECT *
FROM   your_table
WHERE  REGEXP_LIKE( token, '^Oracle Database Token: (1+|123456789|-)\.$' )

But simple string functions/comparisons might be quicker.

Answer 2

I think you want:

where regexp_like(suchstring, '^Oracle Database Token: ([0-9]+|-)[.]'

EDIT:

If you want those specific numbers:

where regexp_like(suchstring, '^Oracle Database Token: (1+|-|123456789)[.]'